The value of 1 +3+5+7+....+ 37 is equal to?
(Only this information is given please solve it)
mayur451998:
361
Answers
Answered by
2
a=1
l=37
d=3-1=2
tn=a+(n-1)d
37 =1+(n-1)2
36=2n-2
n=19
sn=n/2(a+l)
=19/2(1+37)
=19/2×38
=361
l=37
d=3-1=2
tn=a+(n-1)d
37 =1+(n-1)2
36=2n-2
n=19
sn=n/2(a+l)
=19/2(1+37)
=19/2×38
=361
Answered by
0
The value of 1 + 3 + 5 + 7 + ..... + 37 = 324
Given:
1 +3+5+7+....+ 37
To find:
The value of 1 +3+5+7+....+ 37
Solution
Given number sequence 1 +3+5+7+....+ 37 is a AP
Here, first term a = 1
Common difference d = 3-1= 2
last term = 37
Let 37 be the nth term of AP
As we know nth term of AP = a +(n-1)d
=> a + (n-1)d = 37
=> 1 + (n-1)2 = 37
=> 1 +2n -2 = 37
=> 2n = 36
=> n = 18
Number of terms in AP = 18
As we know sum of n terms in AP = n/2 [ 2a+(n-1)d ]
= 18/2 [ 2(1) +(18-1)2 ]
= 9 [ 2 + (17)2 ]
= 9 [ 2 + 34 ]
= 9 [ 36 ]
= 324
Therefore,
The value of 1 + 3 + 5 + 7 + ..... + 37 = 324
#SPJ2
Similar questions