The value of 1+3+5+7+…………………...+ 49 = *
Answers
Answered by
16
Step-by-step explanation:
1,3,5,7,9......49 are in ap
a=1, d=5-3=3-1=2
an=a+(n-1)d
49=1+(n-1)2
49=1+2n-2
49=2n-1
n=(49+1)/2
n=25
Sn=[(n/2){2a+(n-1)d}]
=[(25/2){(2)(1)+(25-1)(2)}]
=[(25/2){2+48}]
=[(25)(25)]
=625
Answered by
3
As we know that the first term of Arithmetic Progression is given as
1st Term of (A.P)⇒
Here given, &
(
is the total number of term)
Now putting given value in Formula
⇒
⇒
⇒
Hence the total number of terms in A.P is
So to find Sum of Arithmetic Progression,
Now putting values in the above equation,
Hence the Sum of Arithmetic Progression
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