Question

The value of (1/3 x²+ y²) (1/3 x² - y²) when x = 3 and y = - 1 is :-​

Answer 1

Answer:

16

Step-by-step explanation:

= (1/3 x^2 - y^2)^2

= (1/3 × 9 +1)^2

=(4^2)

=16