Question

The value of
1/3log 10 ^125- 2log10⁴+ log10³²​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{\frac{1}{3} log(10)^{125} - 2 log(10)^{4} + log(10)^{32} = \frac{217}{3}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies \frac{1}{3} log(10)^{125} - 2 log(10)^{4} + log(10)^{32} \\ \\ \red{\underline \bold{To \: Find :}}\\ \tt: \implies \frac{1}{3} log(10)^{125} - 2 log(10)^{4} + log(10)^{32} = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\\tt: \implies \frac{1}{3} log(10)^{125} - 2 log(10)^{4} + log(10)^{32} \\ \\ \tt: \implies \frac{125}{3} log(10) - 2 \times 4 log(10) + 32 log(10) \\ \\ \tt: \implies \frac{125}{3} log(10) - 8 log(10) + 32 log(10) \\ \\ \tt \circ \: log(10) = 1 \\ \\ \tt: \implies \frac{125}{3} \times 1 - 8 \times 1 + 32 \times 1 \\ \\ \tt: \implies \frac{125}{3} - 8 + 32 \\ \\ \tt: \implies \frac{125 - 24 + 96}{3} \\ \\ \green{\tt: \implies \frac{217}{3} } \\ \\ \green{\tt \therefore \frac{1}{3} log(10)^{125} - 2 log(10)^{4} + log(10)^{32} = \frac{217}{3} }$

Answer 2

$\tt{\huge{\green{Solution_{BQ} \::- }}}$

QUESTION :

Find The value of 1/3log 10 ^125- 2log10⁴+ log10³².

SOLUTION :

In attachment...