Question

The value of [1/√5-2 + 1/√5+2]² is​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

6

Step-by-step explanation:

by using (A+B)^2=A^2+2AB+B^2

={(1/√5+2)^2+2(1/√5-2)(1/√5+2)+(1/√5+2)^2}

={1^2/(√5-2)^2+2(1*1/(√5-2)(√5+2)+1^2/(√5+2)^2}

(a+b)(a-b)=a^2-b^2

={1/5+4√4+4+2*(1/5-4)+1/5+4√5+4}

={1/9+4√4+2+1/9√4}

=(1/9√4+1/9√4+2)

=(2/9√4+2/1)

=2*1+2*(9√4)÷9√4

=2+18+2√4÷9√4

=2+2+2

=6

I hope you will better understand•