Question

The value of 1/

√9−√8

when √8 = 2.828 is

(a) 0 .172 (b) 1.72 (c) 1.162 (d) 2.182​

Answer 1

Answer:

So, we can determine the cube root of 8 which is equal to 2, such as 3√8 = 2. But for numbers which are perfect squares such as 4, 9, 16, 25, etc. the root for them can be determined easily, such as ...

Missing: − ‎| Must include: −

Answer 2

Answer:

5.828

Step-by-step explanation:

$\frac{1}{ \sqrt{9} - \sqrt{8} }$

$= \frac{1}{ \sqrt{9} - \sqrt{8} } \times \frac{ \sqrt{9} + \sqrt{8} }{ \sqrt{9} + \sqrt{8} }$

$= \frac{ \sqrt{9} + \sqrt{8} }{ (\sqrt{9} - \sqrt{8} )( \sqrt{9} + \sqrt{8}) }$

$= \frac{ \sqrt{9} + \sqrt{8} }{ {( \sqrt{9} )}^{2} - {( \sqrt{8} )}^{2} }$

$= \frac{ \sqrt{9} + \sqrt{8} }{9 - 8}$

$= \frac{ \sqrt{9} + \sqrt{8} }{1}$

$= \sqrt{9} + \sqrt{8}$

$= 3 + \sqrt{8}$

$= 3 + 2.828$

$= 5.828$

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