Question

the value of 1.9 bar in form of p by q where p and q are integers and q is not equal to zero​

Answer 1

Let x = 1.9 bar

Then, 10x = 19.9 bar

So, 10x - x = 18

or, 9x = 18

or, x = 2/1

Thus,

$1.9 \: bar = \frac{2}{1}$

HOPE THIS COULD HELP!!!

Answer 2

Answer:

The value of $\frac{p}{q} = \frac{2} {1}$

Step-by-step explanation:

• Now as in the question it is given as
  $x = 1.9999999.......$  ----(1)
• Multiplying by 10 on both the sides of the above equation we get
  $10x=19.99999999..........$   ------(2)
• Now when we substract equation 1 with equation 2 we get
  $10x=19.999999...\\ -x=1.999999999\\= 9x = 18$
• Now as we can see
  $x = \frac{p}{q} = \frac{2}{1}$
  #SPJ2