The value of √1+cos÷1-cos is
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1−cosx1+cosx−−−−−√1−cosx1+cosx
useuse
cos2x=2cos2x−1=1−2sin2xcos2x=2cos2x−1=1−2sin2x
1−(1−2sin2(x2))1+(2cos2(x2)−1)−−−−−−−−−−√1−(1−2sin2(x2))1+(2cos2(x2)−1)
sin2(x2)cos2(x2)−−−−−√sin2(x2)cos2(x2)
tan(x2)
useuse
cos2x=2cos2x−1=1−2sin2xcos2x=2cos2x−1=1−2sin2x
1−(1−2sin2(x2))1+(2cos2(x2)−1)−−−−−−−−−−√1−(1−2sin2(x2))1+(2cos2(x2)−1)
sin2(x2)cos2(x2)−−−−−√sin2(x2)cos2(x2)
tan(x2)
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Hey mate plzz refer to the attachment
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