Question

the value of
1/D-2*sinX is
​

Answer 1

Answer:

I guess you are using the inverse differential operator notation [1/(D^2 + D+1)](sin x), which really amounts to finding a particular solution of the linear differential equation with constant coefficients: y” +y' +y =(sin x), because y'=Dy, y”= (D^2)y = D(Dy). For this, there are several methods but the one easiest to grasp and apply, involves assuming a solution of the form y = A.cos(x)+B.sin(x), where A and B are constants to be determined by actual substitution and comparison of coefficients of cos(x) and sin(x).

Step-by-step explanation:

I hope it helps you

Answer 2

Answer:

(sec X - 2 sin X)

Step-by-step explanation:

Given :- The given expression here is 1/D - (2 × sin X).

To Find :- Value of the above expression.

Solution :-

As the given expression is 1/D - (2 × sin X).

Here let's assume y = sin X.

So, dy/dx = cos X.

We know that dy/dx is sometimes represented as D.

                 D = dy/dx

Now putting the value of D in given expression, we get

= 1/ cos X - ( 2 × sin X)

= (1 - 2 cos X sin X )/cos X

= (1 - 2 cos X sin X ) × sec X           [ ∵ 1 / cos X = sec X ]

= sec X - 2 sec X cos X sin X

= sec X - 2 sin X                               [ ∵ sec X = 1 / cos X]

Therefore, the value of 1/D - (2 × sin X) is ( sec X - 2 sin X ).

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