Math, asked by gayatrimhala, 16 days ago

the value of (1+i)^1000 is​

Answers

Answered by akash4480
0

Answer:

lydllylydlydkydykh

have a nice day

Answered by visankreddy
0

Answer:

-2^500

Step-by-step explanation:

using demoviers theorem you can defined that

by (√2) ^1000(1/√2+i/√2) ^1000

  • cos π =-1
  • sinπ =0
  • so 2 ^500(cos1000π/4 + isin 1000π/4)
  • 2^500(-1)
  • -2^500

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