Question

The value of(1+i)^16 is

Answer 1

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Answer 2

Answer:

${(1 + i)}^{16} \\ = {( {(1 + i)}^{2} )}^{8} \\ = {(1 + {i}^{2} + 2i)}^{8} \\ = {(1 - 1 + 2i)}^{8} \\ = {(2i)}^{8} \\ = {2}^{8} {i}^{8} \\ = 256 \times 1 \\ = 256.$