The value of £¹⁰r.r=1 .rPr is this is a question of PERMUTATIONS
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Step-by-step explanation:
rPr = r! now r*r! can be written as (r+1-1)*r!
= (r+1)*r! – r!
=(r+1)! – r!
1*1P1 = 2! – 1!
2*2P2 = 3! – 2!
3*3P3 = 4! – 3!
So on By adding all of them we get ultimately 11! -1
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