Question

the value of 1/root7-root6 is

Answer 1

Answer:

I hope it will help you.

Answer 2

$\huge \mathfrak \red{answer}$

$\bf{ \underline{ \boxed{ \red{ \tt{ \sqrt{7} + \sqrt{6 \: }}}}}}$

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$\sf \huge \underline{Question}$

the value of

$\rm{ \frac{1}{ \sqrt{7} - \sqrt{6}} }$

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step by step explanation:

$\tt \large \red{⟹ \: \frac{1}{ \sqrt{7} - \sqrt{6}} }$

now we have to rationalize the denominator we get,

$\tt \blue{⟹ \: = \frac{( \sqrt{7} + \sqrt{6}) }{( \sqrt{7} - \sqrt{6}) ( \sqrt{7} + \sqrt{6}) }}$

$\tt \pink{⟹ \: = \frac{( \sqrt{7} + \sqrt{6}) }{( \sqrt{7}) {}^{2} - ( \sqrt{6}) {}^{2} }}$

in the denominator we know that formula of idenity (algebraic)

$\bf{ \underline{ \boxed{ \green {\tt{ {a}^{2} - {b}^{2} = (a + b)(a - b) \: }}}}}}$

$\tt \green{⟹ \: = \frac{( \sqrt{7} + \sqrt{6}) }{(7 - 6)}}$

$\tt \orange{⟹ \: = \frac{( \sqrt{7} + \sqrt{6}) }{1}}$

$\tt \purple{⟹ \: = \sqrt{7} + \sqrt{6}}$

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so,

$\rm \red{⟹ \: = \frac{1}{ \sqrt{7} - \sqrt{6}}} = \sqrt{7} + \sqrt{6}$

i hope it's help uuh