Question

the value of 1/sec theta -tan theta +1/ sec theta + tan theta - 2 sec theta

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\frac{1}{sec \theta - tan \theta} + \frac{1}{sec \theta + tan \theta} \: - 2sec \theta \\ \\ = \frac{sec \theta + tan \theta + sec \theta - tan \theta}{ {sec}^{2} \theta - {tan}^{2} \theta } - 2sec \theta \\ \\ = 2sec \theta - 2sec \theta \\ \\ = 0$

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