Question

the value of 1/sec theta -tan theta +1/sec theta+tan theta-2sec theta is​

Answer 1

Answer:

0 is the answer of the given question (solved in the uploaded photo)

Step-by-step explanation:

Answer 2

$\frac{1}{sec \theta - tan \theta} + \frac{1}{sec \theta + tan \theta} \: - 2sec \theta \\ \\ = \frac{sec \theta + tan \theta + sec \theta - tan \theta}{ {sec}^{2} \theta - {tan}^{2} \theta } - 2sec \theta \\ \\ = 2sec \theta - 2sec \theta \\ \\ = 0$