Question

the value of 1/
Sec²o + 1/cosec²e​

Answer 1

Answer:

Solution :

\sqrt{\dfrac{1\: + \: sin\theta}{1\: - \: sin\theta}}

1−sinθ

1+sinθ

\sqrt{\dfrac{1\:+\: sin\theta}{1\: -\: sin\theta}\times\dfrac{1\: +\: sin\theta}{1\: + \: sin\theta}}

1−sinθ

1+sinθ

×

1+sinθ

1+sinθ

\sqrt{\dfrac{(1\: + \: sin\theta)^{2}}{1^{2}\: - \: sin^{2}\theta}}

1

2

−sin

2

θ

(1+sinθ)

2

\sqrt{\dfrac{(1\: + \: sin\theta)^{2}}{Cos^2\theta}}

Cos

2

θ

(1+sinθ)

2

\dfrac{1\: + \: sin\theta}{Cos\theta}

Cosθ

1+sinθ

\dfrac{1}{Cos\theta}\: + \: \dfrac{sin\theta}{cos\theta}

Cosθ

1

+

cosθ

sinθ

sec\: \theta \: + \: tan\: \thetasecθ+tanθ

Answer 2

Answer:

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Step-by-step explanation:

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