the value of √1+sin theta. √1- sin theta is
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root 1+Sin theta * root 1-sin theta
= root (1+sin theta )(1-sin theta)
= root (1-sin^2 theta)
= root cos^2 theta
= cos theta
= root (1+sin theta )(1-sin theta)
= root (1-sin^2 theta)
= root cos^2 theta
= cos theta
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hello users....
we have to find the value of
√1+sin θ . √1- sin θ =?
solution:-
using formula:
(a+b)(a-b) = a² - b²
&
1-sin²x = cos²x
here
√1+sin θ . √1- sin θ = √(1²-sin² θ)
= √cos² θ
= cos θ answer
⭐✡ hope it helps ✡⭐
we have to find the value of
√1+sin θ . √1- sin θ =?
solution:-
using formula:
(a+b)(a-b) = a² - b²
&
1-sin²x = cos²x
here
√1+sin θ . √1- sin θ = √(1²-sin² θ)
= √cos² θ
= cos θ answer
⭐✡ hope it helps ✡⭐
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