Math, asked by annapurna65, 10 months ago

the value of √1- sin²161° × sec 161°

Answers

Answered by aditioraon637

1

Answer:

=√1- sin²161° × sec161°

[sin²θ + cos²θ = 1]

=√cos²161° × sec161°

=cos161° × sec161°

[secθ = 1/cosθ]

=cos161° × 1/cos161°

= 1

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