Math, asked by mkadhikary1970, 9 months ago

The value of (1 – sin²x)sec²x is *​

Answers

Answered by biligiri
0

Answer:

to evaluate (1-sin²x) sec²x

Step-by-step explanation:

1-sin²x = cos²x [ sin²x+cos²x = 1]

=> cos²x * sec²x

=> cos²x * 1/cos²x

=> 1

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