the value of 1-tan square (45 degree - theta) by 1+ tan square ( 45 degree + theta) is ?
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Correct option is
A
sin2A
=
1+tan
2
(45
o
−A)
1−tan
2
(45
o
−A)
, we know
cos2A=
1+tan
2
A
1−tan
2
A
=cos2(45−A)
=cos(90−2A)
=sin2A
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