the value of 1+tan12/1-tan12
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Correct option is
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3 only
Given Differential equation is xdy=ydx+y
2
dy,
⟹
dy
dx
=
y
x
−y,
⟹
dy
dx
−
y
x
=−y this is a linear differential equation in y,
The integrating factor is
y
1
,
Now the differential equation becomes,
y
1
dy
dx
−
y
2
x
=−1,
⟹
y
x
=∫−1dy
⟹
y
x
=−y+c
,
Given that y(1)=1,
c=2,
to find y(−3),
⟹y
2
−2y−3=0,
Solving the quadratic equation gives,
y=−1 and y=3,
Given that y>0,
∴y=3 only
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