Question

the value of (1+tan9°28')(1+tan35°32')​

Answer 1

Answer:

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Answer 2

1

Step-by-step explanation:

The value of (1+tan9°28')(1+tan35° 32')

(1+tan32) (1+tan 13)=

1+ tan 32+ tan 13+tan 32 tan 13 (1+a)

(1+b)= 1+a+ab

(1+ tan 23)

(1+ tan 22) = 1+ tan 22+ tan 23+ tan 22 tan 23

32+13=45

apply tan on both sides

tan (32+13)= tan (45)

=> tan ( A+ B)=

=> tan 32+ tan 13=1- tan 32 tan 13

=> tan 13 + tan 32 + tan 32 tan 13 = 1

similarly, 22+23=45 => tan 22+ tan 23+ tan 22 tan 23=1

substituting values in above equations =1