Question

The Value of ㏒10 (3/2) + ㏒10 (4/3) + ㏒10 (5/4) + … up to 99 terms is

Answer 1

Theory :-

logₓa + logₓb = logₓab

Solution :-

log₁₀(3/2) + log₁₀(4/3) + log₁₀(5/4) + ... up to 99 terms

= log₁₀(3/2)(4/3)(5/4)...(101/100)

= log₁₀(101/2)

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