Question

The value of (11/cot^2theta-11/cos^2 theta​

Answer 1

Answer:

$\red {Value \: of \: \frac{11}{cot^{2}\theta} - \frac{11}{cos^{2}\theta} }\green {= -11}$

Step-by-step explanation:

$Value \: of \: \frac{11}{cot^{2}\theta} - \frac{11}{cos^{2}\theta}$

$= 11 tan^{2}\theta - 11sec^{2}\theta$

$\boxed { \pink { \frac{1}{cot^{2} \theta } = tan^{2} \theta }}$

$\boxed { \orange { \frac{1}{cos^{2} \theta } = sec^{2} \theta }}$

$= 11(tan^{2} \theta - sec^{2} \theta )$

$= -11( sec^{2} \theta - tan^{2} \theta )$

$= -11 \times 1$

$\boxed { \blue { sec^{2} \theta - tan^{2} \theta = 1 }}$

$= -11$

Therefore.,

$\red {Value \: of \: \frac{11}{cot^{2}\theta} - \frac{11}{cos^{2}\theta}} \green {= -11}$

•••♪

Answer 2

The teratry that ended the first Anglo mysore war was. (A) the teratry of salbai (b) the teratry of madras (c) the teratry of manglore (d) the teratry of Sriarang patanm