Question

The value of (112+122+132+142....202) is

Answer 1

Answer:

The value of (112+122+132+142....202) is

a = 112 d= 122-112=10

Sn=n/2[2a+(n-1)d]

S(10)=10/2[2×112+9×10]

=5[224+90]

=5×314

=1570......ans

Answer 2

Answer:1570

Step-by-step explanation:

The value of (112+122+132+142....202) is

a = 112 d= 122-112=10

Sn=n/2[2a+(n-1)d]

S(10)=10/2[2×112+9×10]

=5[224+90]

=5×314

=1570......ans