Question

The value of 12a²c + 3b - 4ac2 when a =
-1, b = 0 and c = 2 is​

Answer 1

Answer:

Given:

a= -1, b=0, c= 2

$12a^{2} c + 3b -4ac^{2}$

Solution:

$= 12 (-1)^{2} (2)+3(0)- 4(-1)(2)^{2}$

=12(2)+0+16

=24+0+16

=40

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Step-by-step explanation:

Answer 2

Step-by-step explanation:

a= -1

b= 0

c= 2

12*(-1)*(-1)*2 + 3*0 - 4*(-1)*2*2

12*1*2+0-4*4

12*2+0-16

24+0-16

24-16

8 Ans