the value of (17 sec square 29°- 17 cot square 61°)
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Solution :
Given ( 17sec² 29° - 17 cot² 61° )
= 17 [ sec² ( 90 - 61 ) - cot² 61° ]
= 17 [ cosec² 61° - cot² 61 ]
= 17
[ Since , Cosec² A - cot² A = 1 ]
••••
Given ( 17sec² 29° - 17 cot² 61° )
= 17 [ sec² ( 90 - 61 ) - cot² 61° ]
= 17 [ cosec² 61° - cot² 61 ]
= 17
[ Since , Cosec² A - cot² A = 1 ]
••••
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