The value of (2^-1 + 3^-1)^-1 + 4^-1 is
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Given: ( 2^-1 + 3^-1)^1 + 4^-1
Solution:( 1 / 2 + 1 / 3 )^-1 ÷ 1 / 4
= ( 3 + 2 /6 )^-1 ÷ 1/ 4
= ( 5 / 6 )^-1 ÷ 1 / 4
= 6 / 5 ÷ 1 / 4
= 6 / 5 × 4 / 1
= 24 /5
= 4upon 4/5
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