Question

the value of 2-(2-(2-(2-2))) is

Answer 1

Answer:

$\boxed{\large{\underline{ \sf 2}}}$

Step-by-step explanation:

$[2 - \{2 - (2 - (2 - 2)) \}] \\ \\ \implies [2 - \{2 - (2 - 0) \}] \\ \\ \implies [2 - \{2 - 2 \}] \\ \\ \implies [2 - 0] \\ \\ \implies \boxed{ \underline{ \bf 2}}$

Hence, the answer is 2.

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$\large{ \underline{ \underline{ \mathfrak{\heartsuit \:Extra \: Information : \heartsuit }}}}$

Brackets are very important while solving this type of questions. We generally follow the rules of BODMAS, which includes -

B - Brackets

O - of

D - Division

M - Multiplication

A - Addition

S - Subtraction

While solving brackets, smaller one is evaluated first, then middle one and at last the bigger one.

Answer 2

Answer:

2

Step-by-step explanation:

=2-(2-(2-(2-2)))

=2-(2-(2-0))

=2-(2-2)

=2-0

=2

I hope it helps you