Math, asked by rapennagesh07, 6 months ago

the value of [2/3]–²×[3/2]–² is equal to. A)81/16. B)9/4. C)1. D)16/81​

Answers

Answered by djamnouroy2005
8

Answer: C

Step-by-step explanation:

[2/3]–²×[3/2]–² = [ (2^-2)/(3^-2)] × [(3^-2)/(2^-2)]

=> [(1/2^2)/(1/3^2)] × [(1/3^2)/(1/2^2)]

=> [(1/4)/(1/9)] × [(1/9)/(1/4)]

=>[(1/4)×(9/1)] × [(1/9)×(4/1)]

=>(9/4) × (4/9)

=> 36/36

= 1

Answered by sangram0111
0

Given:

The value of \[{\left( {\frac{2}{3}} \right)^2} \times {\left( {\frac{3}{2}} \right)^2}\] is equal to.

Solution:

Evaluate \[{\left( {\frac{2}{3}} \right)^2} \times {\left( {\frac{3}{2}} \right)^2}\],

\[ = \frac{2}{3} \times \frac{2}{3} \times \frac{3}{2} \times \frac{3}{2}\]

=1

Hence, the value of \[{\left( {\frac{2}{3}} \right)^2} \times {\left( {\frac{3}{2}} \right)^2}\] is 1.

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