Math, asked by sara281007, 3 months ago

The value of (2/3)^-5 is

Answers

Answered by ravi2303kumar

1

Answer:

$\frac{243}{32}$

Step-by-step explanation:

$[\frac{2}{3}] ^{-5}$

= $[\frac{3}{2}] ^{5}$

= $\frac{3^5}{2^5}$

= $\frac{243}{32}$

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