the value of 2/√5-√3 is
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We know (A+B)^3 = A^3 + B^3 + 3AB(A+B)
Now put A=( 2+5 )^1/3 and B=( 2-5 )^1/3
So now after substituting we have
{ (2+5 )^1/3 + (2-5)^1/3 }^3
= 2+5 +2 -5 + 3(2+5)(2-5)[ (2+5 )^1/3 + (2-5)^1/3) ]
You want to find ( 2+5 )^1/3 + ( 2-5 )^1/3
let’s take it as X
Now it is X^3 = 4 + 3*(2+5)(2-5)*X
i.e. X^3 = 4 + 3*(4-5)*X
i.e. X^3 = 4 - 3*X
This cubic equation has only one real solution which is “1”.
So, [ ( 2+5 )^1/3 + ( 2-5 )^1/3 ] = 1
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