The value of 2 log 3-1/2 log 16 + log 12
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5
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2log3−1/2log16+log12
Let simplify the expressions into single logarithm,
2log3−1/2log16+log12=2log3−
1/2
log4
2
+log12
=2log3−log4+log12
=log3
2
−log4+log12
=log(9×12)/4
=log(9×3)
=log27
Answered by
0
Answer:
log 27
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