Question

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The value of 2 (sin445° + cot30) – 6(cos245° + tan²30°) is
Hi what is the answer?

Answer 1

Answer:

2 (sin445° + cot30) – 6(cos245° + tan²30°)

Answer is = 4✓3-9 / 2

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Some formula to learn :-

1. tan A = 1/ cot A and cot A = 1 / tan A
2. tan A = sin A / cos A and cot A = cos A / sin A
3. sin ² A + cos ² A = 1
4. cot θ = 1/tan θ
5. tan(x−y) = (tan x–tan y)/ (1+tan x • tan y)

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