Math, asked by Anonymous, 2 days ago

The value of 2(sin⁶θ + cos⁶θ) - 3(sin⁴θ + cos⁴θ) + 1 =
(A) 1
(B) 2
(C) 4
(D) 0

Answers

Answered by thehighriser
4

Answer:

(D) 0

Step-by-step explanation:-

2(sin⁶θ + cos⁶θ) - 3(sin⁴θ + cos⁴θ) + 1

⇒ 2(1 - 3sin²θcos²θ) -3(1 - 2sin²θcos²θ) + 1

⇒ 2 - 6sin²θcos²θ + 6sin²θcos²θ -3 + 1

∴ 2 - 2 = 0

Answered by tjfkroerhtntm
1

Answer:

0 is the answer

Step-by-step explanation:

By sin^2θ + cos^2θ = 1

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