The value of 2(sin⁶θ + cos⁶θ) - 3(sin⁴θ + cos⁴θ) + 1 =
(A) 1
(B) 2
(C) 4
(D) 0
Answers
Answered by
4
Answer:
(D) 0
Step-by-step explanation:-
2(sin⁶θ + cos⁶θ) - 3(sin⁴θ + cos⁴θ) + 1
⇒ 2(1 - 3sin²θcos²θ) -3(1 - 2sin²θcos²θ) + 1
⇒ 2 - 6sin²θcos²θ + 6sin²θcos²θ -3 + 1
∴ 2 - 2 = 0
Answered by
1
Answer:
0 is the answer
Step-by-step explanation:
By sin^2θ + cos^2θ = 1
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