Question

the value of (2°+3°)÷6 is​

Answer 1

$\red{ The \:value \: of \: (2^{0} + 3^{0}) \div 6 }$

$= \frac{(2^{0} + 3^{0})}{6}$

$= \frac{1+1}{6}$

/* By Exponential Law */

$\boxed{\pink{ a^{0} = 1 }}$

$= \frac{2}{6}$

$= \frac{1}{3}$

Therefore.,

$\red{ The \:value \: of \: (2^{0} + 3^{0}) \div 6 }\green { = \frac{1}{3} }$

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