Question

The value of 20=6×-4 is​

Answer 1

Step-by-step explanation:

x, y={3/2y in terms of y, 2/3x in terms of x}. Hence, x:y::3:2 and the domain of x and y is infinite. Any real numbers R where the ratio of x:y is 3:2 will return a difference that is consistent with the original equation 4x-6y=0.

PREMISES

4x-6y=0

CALCULATIONS

4x-6y=0

4x-(6y-6y)=0+6y

4x-0=0+6y

4x=6y

4x/4=6y/4

x=6/4y

x=3/2y

x=

3/2y in terms of y

and,

if x=3/2y, then

y=

2/3x

PROOF

If x, y={3/2y, 2/3x} and x:y::3:2, then x and y can be any real numbers R in the ratio of 3:2.

(1) Where y=10 and x=15, then

4x-6y returns

4(15)-6(10)=

60–60=0

and,

(2) Where y=35 and x=52.5

4x-6y returns

4(52.5)-6(35)=

210–210=0

and,

(3) Where y=1/2 and x=3/4

4x-6y returns

4(3/4)-6(1/2)=

3–3=0

and so forth

Answer 2

Step-by-step explanation:

20 = -24

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