Question

The value of |21-(l3+2)x2| is​

Answer 1

Answer:

since all arms are connected between two nodes, hence PD across both nodes will be same and current through 6 Ω resistance will be I=I

1

+I

2

+I

3

Now, PD across nodes through each branch will be

V=6I=8−I

1

=9−2I

2

=10−3I

3

thish gives

I

1

=8−V ...(1)

I

2

=

2

9−V

...(2)

I

3

=

3

10−V

...(3)

solving for I=I

1

+I

2

+I

3

we get, I=(8+

2

9

+

3

10

)−(1+

2

1

+

3

1

)V=

6

95

−

6

11

V

and using it in V=6I=95−11V , we get value of V=

12

95

=6 volt

using value of V in eq. 1 , 2 and 3 we get value of I

1

=2A,I

2

=1.5A,I

3

=1.33 A

Answer 2

Answer:

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