The value of |21-(l3+2)x2| is
Answers
Answered by
2
Answer:
since all arms are connected between two nodes, hence PD across both nodes will be same and current through 6 Ω resistance will be I=I
1
+I
2
+I
3
Now, PD across nodes through each branch will be
V=6I=8−I
1
=9−2I
2
=10−3I
3
thish gives
I
1
=8−V ...(1)
I
2
=
2
9−V
...(2)
I
3
=
3
10−V
...(3)
solving for I=I
1
+I
2
+I
3
we get, I=(8+
2
9
+
3
10
)−(1+
2
1
+
3
1
)V=
6
95
−
6
11
V
and using it in V=6I=95−11V , we get value of V=
12
95
=6 volt
using value of V in eq. 1 , 2 and 3 we get value of I
1
=2A,I
2
=1.5A,I
3
=1.33 A
Answered by
0
Answer:
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