Math, asked by ParulMiglani, 4 months ago

The value of 22−−√3−−−−√4 is equal to
(a) 2–16
(b) 2-6
(c) 216
(d) 26​

Answers

Answered by pashminayak12
117

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Answered by isha00333
21

Note: the given question is incorrect as it should be as follows:

The value of \[\sqrt[4]{{\sqrt[3]{{{2^2}}}}}\] is equal to

(a) 2^{\frac{1}{6} }                     (b) 2^{6}                      (c) 216                  (d) 26​

Given:  \[\sqrt[4]{{\sqrt[3]{{{2^2}}}}}\].

To find: the value of the given expression.

Solution:

Simplify the given expression.

\[\sqrt[4]{{\sqrt[3]{{{2^2}}}}} = {\left( {{{\left( {{2^2}} \right)}^{\frac{1}{3}}}} \right)^{\frac{1}{4}}}\]

\[ \Rightarrow \sqrt[4]{{\sqrt[3]{{{2^2}}}}} = {2^{2 \times \frac{1}{3} \times \frac{1}{4}}}\]

\[ \Rightarrow \sqrt[4]{{\sqrt[3]{{{2^2}}}}} = {2^{\frac{1}{6}}}\]

Therefore, the value of \[\sqrt[4]{{\sqrt[3]{{{2^2}}}}}\] is \[{2^{\frac{1}{6}}}\].

Hence, the correct answer is option (a). i.e., \[{2^{\frac{1}{6}}}\].

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