Question

The value of {(23 + 2^2)^2/3 +(140 - 29)1/2)^2 is​

Answer 1

Simplify:

Step-by-step explanation:

$\ Given \ value:\\\\\{((23+2^2)^{\frac{2}{3}}+(140-29)\frac{1}{2})^2\}\\\\\ Solution:\\\\\{((23+2^2)^{\frac{2}{3}}+(140-29)\frac{1}{2})^2\}\\\\\rightarrow \{((23+4)^{\frac{2}{3}}+(111)\times \frac{1}{2})^2\}\\\\\rightarrow \{((27)^{\frac{2}{3}}+(111)\times \frac{1}{2})^2\}\\\\\rightarrow \{((3^3)^{\frac{2}{3}}+\frac{111}{2})^2\}\\\\\rightarrow \{((3)^2+\frac{111}{2})^2\}\\\\\rightarrow \{(9+\frac{111}{2})^2\}\\\\\rightarrow \{(\frac{18+111}{2})^2\}\\\\\rightarrow \{(\frac{129}{2})^2\}$

$\rightarrow (64.5)^2\\\\4,160.25$

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