Question

The value of {(23 + 2^2)^2/3+ (140 – 29)^1/2)^2 is
(a) 196
(b) 289
(c) 324​

Answer 1

Answer:

${(23 + 4)}^{ \frac{2}{3} } + {(( {121)}^{ \frac{1}{2} } })^{2}$

${27}^{ \frac{2}{3} } + {11}^{2}$

${ ({3}^{3}) }^{ \frac{2}{3} } + 121$

${3}^{2} + 121$

$9 + 121$

$= 130$