The value of 2³+(2²×2¹)‐(2³)²
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it's answer will be 0 at last..
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Keep taking 2 common. 2(2^3–2^2–2–1)=2(2(2^2–2–1)-1)=2(2(2(2–1)-1)-1). Now solve from in to out.
Also (2^n) -1=sum of all powers of 2 from 0 to n-1.
This is what computers are based on loosely.
Alternately grouping the even powers and odd powers of two and then taking the common factors also gives the answer.
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