Question

the value of 251 square minus 249 square is​

Answer 1

$\huge\underline{\mathbb\red{✰Q}\green{u}\mathbb\blue{e}\purple{s}\mathbb\orange{ti}\pink{on}}\:$,

• [ 251^2 - 249^2 ]

_____________________

to find the value of [ 251^2 - 249^2 ]

$\huge\underline{\mathbb\red{➻A}\green{N}\mathbb\blue{S}\purple{W}\mathbb\orange{E}\pink{R}}\:$,

=> [ 251^2 - 249^2 ]

=> [ 251 - 249 ] [ 251 + 249 ]

=> ( 2 ) ( 500 )

=> 1000 ans.

Answer 2

Answer: The value of $251^{2} - 249^{2}$ is $1000$.

Step-by-step explanation:

Given: $251^{2} - 249^{2}$

To find: We have to fin the value of $251^{2} - 249^{2}$

Explanation:

on applying the identity $a^{2} - b^{2} = (a+b)(a-b)$

                 where $a = 251$ and $b = 249$

⇒                             $251^{2} - 249^{2}$ $=( 251$ $+249)$ $(251-249)$

                                                   $=500$ × $2$

                                                   $= 1000$

Hence, the value of $251^{2} - 249^{2}$ is $1000$.

the difference of two squares is a squared (multiplied by itself) number subtracted from another squared number. Every difference of squares may be factored according to the identity $a^{2} - b^{2} = (a+b)(a-b)$.

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