Question

The value of [29− (−2){6−(7−3)}]÷ [3 × {5+ (−3) ×(−2)}] is
(A) 0 (B) 1
(C) 2 (D) 3

Answer 1

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Given :

[ 29 - ( - 2 ) { 6 - ( 7 - 3 ) } ] ÷ [ 3 × { 5 + ( - 3 ) × ( - 2 ) } ]

Using BODMAS rule

= [ 29 - ( - 2 ) { 6 - ( 4 ) } ] ÷ [ 3 × { 5 + ( - 3 × - 2 ) } ]

= [ 29 - ( - 2 ) { 2 } ] ÷ [ 3 × { 5 + 6 } ]

= [ 29 - ( - 2 × 2 ) ] ÷ [ 3 × 11 ]

= [ 29 - ( - 4 ) ] ÷ 33

= [ 29 + 4 ] ÷ 33

= 33 ÷ 33

= 33 / 33

= 1

Hence, Option (B) is correct.

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