Question

the value of 2cot (7/6) + 4tan? (1/6) – 3cosec(1/6) is​

Answer 1

Answer: cot2(π/6) + 4 tan2(π/6) – 3 cosec π/6

cot2(π/6) + 4 tan2(π/6) – 3 cosec π/6= 2(√3)2 + 4(1/√3)2 – 3(2)

cot2(π/6) + 4 tan2(π/6) – 3 cosec π/6= 2(√3)2 + 4(1/√3)2 – 3(2)= 2(3) + 4(1/3) – 6

cot2(π/6) + 4 tan2(π/6) – 3 cosec π/6= 2(√3)2 + 4(1/√3)2 – 3(2)= 2(3) + 4(1/3) – 6= 6 + (4/3) – 6

cot2(π/6) + 4 tan2(π/6) – 3 cosec π/6= 2(√3)2 + 4(1/√3)2 – 3(2)= 2(3) + 4(1/3) – 6= 6 + (4/3) – 6= 4/3