Math, asked by 1998psamal, 7 months ago

The value of 2log2+log3log48−log4 is​

Answers

Answered by Anonymous
0

 

Answer

Solution :

a)log510⋅log210+(log210)2

log10102log10.210+...

(1−log2)(1+log2)+(log2)2

1−(log2)2+(log2)2=1

b)2log2+log3log48−log4=log4+log2log48−log4

log4⋅3log(484)=log12log12=1

c)−log5log3(915)12

−log5log3325⋅2

−log

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