Question

the value of 2sin^(2)30°-3cos^(2)45°​

Answer 1

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$: \implies \sf2 \sin^230°-3 \cos^245° \\ \\: \implies \sf 2 \times { \bigg( \frac{1}{2} \bigg) }^{2} - 3 \times \bigg({ \frac{1}{ \sqrt{2} }\bigg) }^{2} \\ \\: \implies \sf 2 \times \frac{1}{4} - 3 \times \frac{1}{2} \\ \\ : \implies \sf \frac{1}{2} - \frac{3}{2} \\ \\ : \implies \sf \frac{1 - 3}{2} \\ \\ : \implies \sf \frac{ - 2}{2} \\ \\\large : \implies \boxed{\sf - 1 }$

Answer 2

SOLUTION...

\begin{gathered}: \implies \sf2 \sin^230°-3 \cos^245° \\ \\: \implies \sf 2 \times { \bigg( \frac{1}{2} \bigg) }^{2} - 3 \times \bigg({ \frac{1}{ \sqrt{2} }\bigg) }^{2} \\ \\: \implies \sf 2 \times \frac{1}{4} - 3 \times \frac{1}{2} \\ \\ : \implies \sf \frac{1}{2} - \frac{3}{2} \\ \\ : \implies \sf \frac{1 - 3}{2} \\ \\ : \implies \sf \frac{ - 2}{2} \\ \\\large : \implies \boxed{\sf - 1 }\end{gathered}

:⟹2sin

2

30°−3cos

2

45°

:⟹2×(

2

1

)

2

−3×(

2

1

)

2

:⟹2×

4

1

−3×

2

1

:⟹

2

1

−

2

3

:⟹

2

1−3

:⟹

2

−2

:⟹

−1