Question

the value of 2tan^2 60°- 4cos^2 45° - 3sec^2 45°

Answer 1

tan60=√3
cos 45=1/√2
sec 45 =√2

therefore,
$2 {tan}^{2} 60 - 4 {cos}^{2} 45 - 3 {sec}^{2} 45 = 2 \times { \sqrt{3} }^{2} - 4 \times { \frac{1}{ \sqrt{2} } }^{2} - 3 \times { \sqrt{2} }^{2}$
= -2

hope this helps
mark branliest if helped

Answer 2

Hey mate here is your answer
tan60=√3
cos 45=1/√2
sec 45 =√2

therefore,
2 {tan}^{2} 60 - 4 {cos}^{2} 45 - 3 {sec}^{2} 45 = 2 \times { \sqrt{3} }^{2} - 4 \times { \frac{1}{ \sqrt{2} } }^{2} - 3 \times { \sqrt{2} }^{2}2tan​2​​60−4cos​2​​45−3sec​2​​45=2×√​3​​​​2​​−4×​√​2​​​​​1​​​2​​−3×√​2​​​​2​​
= -2

pls mark brainlist answer