Question

The value of 2tan30/1-tan^230 is
(a)sin60
(b)cos60
(c)tan60
(d)sin30​

Answer 1

Answer:

hii

your answer is here !

Step-by-step explanation:

tan 30 = 1/√3

then 2tan30/(1+tan^2 30) is= 2×1/√3 / (1+(1/√3)²)

= 2/√3 / (1+1/3)         in brackets by taking 3 as lcm we get

= 2/√3 / (3+1/3)

= 2/√3 / 4/3

= 2/√3×3/4

= 3 / 2√3   (3 can be written as √3×√3)

= √3×√3 / 2√3

= √3/2

= cos 30

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Answer 2

Hey, here is your answer...

$= > \: we \: know \: that \\ \\ (2 \tan( \alpha )) \div (1 - { \tan }^{2}( \alpha )) \: = \: \tan(2 \alpha ) \\ \\ here \: \alpha \: = </em><em>30</em><em>°</em><em>\\ \\ therefore \: 2 \alpha \: = \: </em><em>60</em><em>°</em><em> \\ \\ and \: \tan(</em><em>60</em><em>°</em><em>) \: = \: \sqrt{3} \\ \\ so \: your \: answer \: is \: \sqrt{3}$

And it is equal to tan(60°)

Hope this helps you...

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