Question

The value of (3^0+4-¹)×2² is​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4=

As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4= 4

As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4= 45

As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4= 45

As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4= 45 ×4

As we know that,n 0 =1n −1 = n1 Therefore,(3 0 +4 −1 )×2 2 =(1+ 41 )×4=( 44+1 )×4= 45 ×4=5